Abstract. Let $T$ be an absolutely continuous polynomially bounded operator, and let $\theta $ be a singular inner function. It is shown that if $\theta (T)$ is invertible and some additional conditions are fulfilled, then $T$ has nontrivial hyperinvariant subspaces.
DOI: 10.14232/actasm-018-582-z
AMS Subject Classification
(1991): 47A15; 47A60, 47A10
Keyword(s):
hyperinvariant subspace,
polynomially bounded operator
Received September 12, 2018 and in final form April 4, 2019. (Registered under 82/2018.)
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